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5x+30=0.25x^2
We move all terms to the left:
5x+30-(0.25x^2)=0
We get rid of parentheses
-0.25x^2+5x+30=0
a = -0.25; b = 5; c = +30;
Δ = b2-4ac
Δ = 52-4·(-0.25)·30
Δ = 55
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{55}}{2*-0.25}=\frac{-5-\sqrt{55}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{55}}{2*-0.25}=\frac{-5+\sqrt{55}}{-0.5} $
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